With the Equation 6H2O + 6CO2 --> C6H12O6 + 6O2 How many grams of water are needed to make the above amount of glucose if you start with 88.0g of CO2?

1 Answer
Noah G
Mar 8, 2018

The question doesn't make much sense as it is so I will show you how to find the amount of glucose, given #88.0# g of #CO_2#. We have:

#6H_2O + 6CO_2 -> C_6H_12O_6 + 6O_2#

We must convert the carbon dioxide to moles. We know that the molar mass of #CO_2# is #12 + 2(16) g/"mol" = 44 g/"mol"#

#88.0 g * (mol)/(44 g) = 2 mol#

Now we look at our chemical equation's mole ratios. We can see that #6# moles of #CO_2# gives #1# mole of #C_6H_12O_6# therefore, we will have #1/3# mol of glucose. The molar mass of glucose is #6(12)+ 12(1) + 6(16) = 180 g/"mol"#.

#1/3 " mol" * 180 g/"mol" = 60 g #

Therefore, #60# grams of glucose will be produced.

Hopefully this helps!

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