Will, Micah, and sue went to dinner, Will paid 1/3 of the dinner bill Miah and Sue paid the ratio 2:5. If Sue paid $6 more than Will how much did the dinner cost?

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Will, Micah, and sue went to dinner, Will paid 1/3 of the dinner bill Miah and Sue paid the ratio 2:5. If Sue paid $6 more than Will how much did the dinner cost?

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Answer 1 · 2017-04-21T11:54:10

The dinner cost was $$42$

Explanation:

Let the dinner cost was $$x$
Will paid $x/3$
Miah paid $2/7$ of remaining $(1-1/3)x=2/3 x$ i.e $4/21 x$
Sue paid $5/7$ of remaining $(1-1/3)x=2/3 x$ i.e $10/21 x$
Sue paid $$6$ more than Will. $:.10/21 x -1/3 x=6 or 3/21 x=6 or x=$42$
Will paid $42/3=$1$ 4, Miah paid $4/21*42=$8$ ,Sue paid $10/21*42=$20$
The dinner cost was $$42$ .[Ans]

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Will, Micah, and sue went to dinner, Will paid 1/3 of the dinner bill Miah and Sue paid the ratio 2:5. If Sue paid $6 more than Will how much did the dinner cost?

1 Answer

Explanation:

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