Why would tension be smaller if the string were parallel to the lab bench?
1 Answer
Let
Taking East as positive
External forces responsible for the magnitude of acceleration of masses when considered as single object
(M+m)a=mgcostheta-mu(Mg-mgsintheta)(M+m)a=mgcosθ−μ(Mg−mgsinθ) ......(1)
For Block it is
a=T_x/Ma=TxM
=>a=(Tcostheta)/M⇒a=TcosθM
=>T=(Ma)/costheta⇒T=Macosθ
=>T=(M(mgcostheta-mu(Mg-mgsintheta)))/((M+m)costheta)⇒T=M(mgcosθ−μ(Mg−mgsinθ))(M+m)cosθ .....(2)
Rewriting it as
T=a-b/costheta+ctanthetaT=a−bcosθ+ctanθ
wherea,b and ca,bandc are system parameters defined with help of (2) not dependent onthetaθ
We see that
-1/costheta−1cosθ . ForTT to be a smaller numbercosthetacosθ term must be maximum. We know thatcosthetacosθ has a maximum value=1=1 fortheta=0^@θ=0∘ tanthetatanθ . ForTT to be a smaller number,tanthetatanθ term must be zero. We know thattanthetatanθ has a value=0=0 fortheta=0^@θ=0∘ .
Hence, we see that tension will be smaller if the string connecting the block were parallel to the lab bench.