Why does tan equal to sin/cos?

1 Answer
Apr 15, 2015

The best answer to this question depends on the definitions you're using for the trigonometric functions:

Unit circle:

t correspond to point (x,y) on the circle x^2+y^2 =1
Define:
sint = y, , cos t = x, , tant = y/x

The result is immediate.

Point (x,y) on the terminal side of t and r=sqrt(x^2+y^2)

sint = y/r, , cos t = x/r, , tant = y/x

sint/cost = (y/r)/(x/r)= (y/r)*(r/x) = y/x = tan t

Right triangle

sin theta = "opposite"/"hypotenuse" = "opp"/"hyp"

cos theta = "adjacent"/"hypotenuse" = "adj"/"hyp"

sin theta = "opposite"/"adjacent" = "opp"/"adj"

The result follow from :

sin theta / cos theta = ("opp"/"hyp")/("adj"/"hyp") = ("opp"/"hyp")*("hyp"/"adj") = "opp"/"adj" = tan theta