Which would contain 9.03 × 10^23 oxygen atoms? A) 0.25 mol aluminium oxide B) 0.75 mol sulfur dioxide C) 1.5 mol sulfur trioxide D) 3.0 mol water

2 Answers
anor277
Nov 25, 2017

Well one mole of stuff specifies #6.022xx10^23# individual items of stuff.....

Explanation:

But of course we must specify the item. In the first scenario we gots #0.25*mol# #"aluminium oxide"#, i.e. #Al_2O_3#..approx. #4.5xx10^23*"oxygen atoms"#...

And in the second scenario we gots #6.022xx10^23*mol^-1xx2xx0.75*mol# #"oxygen atoms"=9.0xx10^23*"oxygen atoms"#. So it looks like scenario 2 is the winner. And scenario 3 and 4 contain too many oxygen atoms to fulfil your given criterion.

LM
Nov 25, 2017

#B#

Explanation:

#0.75# mol sulphur dioxide = #0.75# mol of sulphur #+1.5# mol of oxide

#1.5# mol = #1.5 * 6.02 * 10^23 = 9.03*10^23#

#1.5# mol of oxide = #0.75# mol dioxide = #9.03*10^23# oxygen atoms

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