Which Quadrants contain the solution to this system of inequalities y≥1/-3x+3 and y>3/4x-1?

1 Answer
Sep 2, 2015

Solving system of linear equations:
(1) y >= - x/2 + 3yx2+3
(2) y > (3x /4) - 1y>(3x4)1

Ans: Quadrant I and II

Explanation:

First graph the Line y1 -> y = - x/4 + 3.y=x4+3.
The solution set of inequality (1) is the area above this line. Color it
Next, graph the Line 2 --> y = (3x)/4 - 1.y=3x41.
The solution set of inequality (2) is the area above this Line 2.
Color it.
The compound solution set is the commonly shared area. It is located in Quadrant I and II.
Note. Because of the sign (=), the Line 1 is included in the solution set of inequality (1).