Which of the following compounds is/are polar covalent: $H_{2} O$ $H_2O$ , $C a C l_{2}$ $CaCl_2$ , $N_{2}$ $N_2$ , $C H_{4}$ $CH_4$ , $H N O_{3}$ $HNO_3$ ? How is this determined?

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Which of the following compounds is/are polar covalent: $H_{2} O$ $H_2O$ , $C a C l_{2}$ $CaCl_2$ , $N_{2}$ $N_2$ , $C H_{4}$ $CH_4$ , $H N O_{3}$ $HNO_3$ ? How is this determined?

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Answer 1 · 2017-05-24T06:01:16

Molecular polarity is the result of the vector sum of the individual bond dipoles..........

Explanation:

And with ionic species, because the charges are formally SEPARATED, we generally do not speak of polarity. So for $C a C l_{2}$ $CaCl_2$ we speak of an ionic salt.

On the other hand, for $^{δ +} H - δ - O - H$ $""^(delta+)H-stackrel(delta-)O-H$ , $^{δ +} H - δ - O + N (= O) (- O^{-})$ $""^(delta+)H-stackrel(delta-)Ostackrel(+)N(=O)(-O^(-))$ (the nitrogen is also formally quaternized), there is charge separation, polarity, and thus these are polar covalent molecules.

On the other, other hand, for $N_{2}$ $N_2$ , and $C H_{4}$ $CH_4$ , there is NO polarity, no charge separation, and these species are classic non-polar molecules.

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Which of the following compounds is/are polar covalent: $H_{2} O$ $H_2O$ , $C a C l_{2}$ $CaCl_2$ , $N_{2}$ $N_2$ , $C H_{4}$ $CH_4$ , $H N O_{3}$ $HNO_3$ ? How is this determined?

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Which of the following compounds is/are polar covalent: H_2OH2OH_2O, CaCl_2CaCl2CaCl_2, N_2N2N_2, CH_4CH4CH_4, HNO_3HNO3HNO_3? How is this determined?

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Which of the following compounds is/are polar covalent: $H_{2} O$ $H_2O$ , $C a C l_{2}$ $CaCl_2$ , $N_{2}$ $N_2$ , $C H_{4}$ $CH_4$ , $H N O_{3}$ $HNO_3$ ? How is this determined?