When you draw out this compound, where is the double bond? 3-METHYL HEXENE

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When you draw out this compound, where is the double bond? 3-METHYL HEXENE

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Answer 1 · 2018-06-06T18:23:14

With all these problems you draw out the hydrocarbyl chain FIRST....

Explanation:

And so we got $"n-hexane..."$

$H_3stackrel1C-CH_2stackrel3CH_2stackrel4CH_2CH_2stackrel6CH_3$ ...but you specify $"3-hexene"...$ ...between $stackrel3C$ and $stackrel4C$ , there is an olefinic bond....and hence we got...

$H_3stackrel1C-CH_2stackrel3CH=stackrel4CHCH_2stackrel6CH_3$ ..

And so we got $"3-hexene"$ , but $"3-methylhexene"$ was specified…

$H_3stackrel1C-CH_2stackrel3C(CH_3)=stackrel4CHCH_2stackrel6CH_3$

,,now this structure will generate TWO geometric isomers. What are they?

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When you draw out this compound, where is the double bond? 3-METHYL HEXENE

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Explanation:

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