When the pH of a solution is 12.83, what is [H+]?
1 Answer
Jun 23, 2017
There are
Explanation:
Because pH is a logarthmic scale, we can use the formula:
=>
=>
=> Where
We can now just sub in the values and solve for [
#[H^+] = 10^("-pH")#
# = 10^(-(12.83))#
# = 1.479108388 xx 10^-13#
We can round (if required) to
Thus, there are
Hope this helps :)