When sodium chlorate (I), NaClO is heated, sodium chlorate (V) and sodium chloride are formed. What is the ionic equation for this reaction? What type of reaction is this?

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When sodium chlorate (I), NaClO is heated, sodium chlorate (V) and sodium chloride are formed. What is the ionic equation for this reaction? What type of reaction is this?

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Answer 1 · 2017-12-09T21:17:40

This is a $disproportionation reaction$ $"disproportionation reaction"$ , in which chlorine is $OXIDIZED$ $"OXIDIZED"$ and $REDUCED...$ $"REDUCED..."$

Explanation:

$Oxidation:$ $"Oxidation:"$
$I^{+} C l O^{-} + 2 H_{2} O \to V^{+} C l O_{3}^{-} + 4 H^{+} + 4 e^{-}$ $stackrel(I^+)ClO^(-) + 2H_2Orarr stackrel(V^+)ClO_3^(-)+4H^+ +4e^(-)$ $(i)$ $(i)$

$Reduction:$ $"Reduction:"$
$I^{+} C l O^{-} + 2 H^{+} + 2 e^{-} \to^{-} I C l^{-} + H_{2} O$ $stackrel(I^+)ClO^(-) + 2H^+ + 2e^(-) rarr stackrel(""^(-)I)Cl^(-)+H_2O$ $(i i)$ $(ii)$

And so we takes.... $(i) + 2 \times (i i)$ $(i)+2xx(ii)$

$stackrel(I^+)ClO^(-) +2stackrel(I^+)ClO^(-) cancel(+2H_2O+ 4H^+ + 4e^(-))rarr stackrel(V^+)ClO_3^(-)+2stackrel(""^(-)I)Cl^(-)cancel(+4H^+ +2H_2O+4e^(-))$

...to give....after cancellation....

$stackrel(I^+)ClO^(-) +2stackrel(I^+)ClO^(-) rarr stackrel(V^+)ClO_3^(-)+2stackrel(""^(-)I)Cl^(-)$

Chlorine is simultaneously reduced and oxidized....i.e. a $"disproportionation..."$

Is this balanced with respect to mass and charge? Don't trust my 'rithmetic....

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When sodium chlorate (I), NaClO is heated, sodium chlorate (V) and sodium chloride are formed. What is the ionic equation for this reaction? What type of reaction is this?

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Explanation:

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