When 6.25 g of AgNO3 reacts with 4.12 g of NaCl to form NaNO3 and AgCl, what is the limiting reactant?
1 Answer
Nov 2, 2015
Molecular mass of
Explanation:
The reaction (which perhaps I should have written first!) is:
The nitrate and sodium ions are simply along for the ride and remain in solution. Note that the silver chloride precipitate would be exceptionally curdy and hard to handle.
So what are the molar quantities of silver nitrate and sodium chloride in this rxn? For precious metals, why is it a good idea that the precipitating reagent be present in excess?