When 30.0 moles of zinc reacts with excess $H_3PO_4$ , how many grams of hydrogen are produced?

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Answer 1 · 2016-12-04T18:00:01

$30$ $"g"$

$3"Zn" + 2"H"_3"PO"_4 -> "Zn"_3("PO"_4)_2 + 3"H"_2$

The molar ratio of zinc: hydrogen is $3:3$ so moles of zinc = moles of hydrogen.

$"m"="nM"=30xx1=30$ $"g"$

When 30.0 moles of zinc reacts with excess H_3PO_4H_3PO_4, how many grams of hydrogen are produced?