When 2.00 moles of #KNO_3# dissociate in aqueous solution, how many ions are formed?

Avogadro's Number: #6.02*10^23#

Do you double #1.20*10^24#?

1 Answer
anor277
May 13, 2018

Why FOUR MOLES of ions.....

Explanation:

WE investigate the reaction....

#KNO_3(s)stackrel(H_2O)rarrK^+ +NO_3^(-)#

Now supposing (somehow) you had 24, i.e. 2 dozen, potassium nitrate formula units. Would you not agree that these 2 dozen particles would gives 48, i.e. four dozen ions...2 dozen potassium ions, and 2 dozen nitrate ions...?

And here we go from a dozen to a mole, i.e. #6.022xx10^23*mol^-1#

And so ....

#"moles of ions"-=2xx6.022xx10^23*mol^-1xx2.00*mol=2.41xx10^24*"individual ions..."#

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