What would be the mass of three moles of ammonia?

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Answer 1 · 2017-12-24T18:50:30

This is ammonia,

$NH_3$ where $AW approx (17g)/(mol)$

Hence,

$3mol * (17g)/(mol) approx 51g$

is the mass given your data.

Answer 2 · 2017-12-25T00:11:25

See the step process below..

Recall..

$"no of moles" = ("mass")/("molar mass")$

$n = m/(Mm)$

Where;

$n = 3mols$

$Mm = NH_3 = 14 + (1)3 = 14 + 3 = 17gmol^-1$

$m = ?$

Making $m$ the subject..

$m = n xx Mm$

$m = 3mols xx 17gmol^-1$

$m = 51g$