What volume of a 0.0320 M #KCN# solution contains #8.50x10^-3# mol of #KCN#? Chemistry Solutions Solutions 1 Answer anor277 May 14, 2017 Approx. #270*mL#............ Explanation: #"Molarity"="Moles of solute"/"Volume of solution"# And thus #"Volume of solution"="Moles of solute"/"Molarity"# #(8.50xx10^-3*mol)/(0.0320*mol*L^-1)=0.266*1/(1/(L))=0.266*L# Answer link Related questions How are solution, solute, and solvent related? Why do solutions become saturated? How does temperature affect solutions? How does a solution differ from a colloid? Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. How does buffering a solution change the solutions behavior? How does Benedict's solution change colour? Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... How do solutions differ from suspensions? How does a solution differ from a compound? See all questions in Solutions Impact of this question 7872 views around the world You can reuse this answer Creative Commons License