What transformation can you apply to #y=sqrtx# to obtain the graph #y=sqrt(-2x)-8#?

Question

1167 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-02T03:22:07

.Reverse x-axis by #x to -x#, apply the scalar multiple 2 and shift

the origin to (0, -8). In brief, #(x, y) to (-2x, y+8)#

Reverse x-axis by #x to -x#, apply the scalar multiple 2 and shift

the origin to (0, -8).

Now, #y = sqrtx# transforms to #y = sqrt(-2x)-8#, referred to the new

axes.

The two graphs reveal the process in the transformation that incides

x-scaling by the factor 2.

graph{xy(y-sqrtx)=0 [-10, 10, -5, 5]}

graph{-(y+8)(y-sqrt(-2x)+8)=0x^2 [-20, 20, -10, 10]}

.