What torque would have to be applied to a rod with a length of $8 m$ $8 m$ and a mass of $8 k g$ $8 kg$ to change its horizontal spin by a frequency $15 H z$ $15 Hz$ over $4 s$ $4 s$ ?

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What torque would have to be applied to a rod with a length of $8 m$ $8 m$ and a mass of $8 k g$ $8 kg$ to change its horizontal spin by a frequency $15 H z$ $15 Hz$ over $4 s$ $4 s$ ?

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Answer 1 · 2016-02-08T12:57:29

$L = - 1408 \cdot π$ $L=-1408*pi$

Explanation:

$α : angular acceleration$ $alpha :"angular acceleration"$
$L : Torque$ $L: "Torque"$
$I : moment of inertia$ $I: "moment of inertia"$
$Torque is given by formula : L = α \cdot I$ $"Torque is given by formula": L=alpha *I$
$L=2*pi(omega_l-omega_i)/(Delta t)*I$
$L=2*pi(4-15)/4 *I$
$L=-11 *pi/4 *I$
$I=m*r^2$
$I=8*64=512$
$L=-11*pi/4 *512$
$L=-11*128*pi$
$L=-1408*pi$

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What torque would have to be applied to a rod with a length of $8 m$ $8 m$ and a mass of $8 k g$ $8 kg$ to change its horizontal spin by a frequency $15 H z$ $15 Hz$ over $4 s$ $4 s$ ?

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What torque would have to be applied to a rod with a length of $8 m$ $8 m$ and a mass of $8 k g$ $8 kg$ to change its horizontal spin by a frequency $15 H z$ $15 Hz$ over $4 s$ $4 s$ ?