What torque would have to be applied to a rod with a length of $6 m$ $6 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency $5 H z$ $5 Hz$ over $4 s$ $4 s$ ?

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What torque would have to be applied to a rod with a length of $6 m$ $6 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency $5 H z$ $5 Hz$ over $4 s$ $4 s$ ?

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Answer 1 · 2016-09-03T11:41:51

$τ = 657.75$ $tau=657.75$ $N - m$ $N-m$

Explanation:

The torque is given by:
$τ = I \cdot . ω = I \cdot \frac{ω}{t}$ $tau=I*dot omega=I*omega/t$
where $I$ $I$ is the moment of Inertia of the horizontal spinning rod which is given by: $I = \frac{m \cdot l^{2}}{12}$ $I=(m*l^2)/12$
and $ω$ $omega$ , the angular velocity is given by $ω = 2 π \cdot f$ $omega=2pi*f$

So, from the given data
$I = \frac{3 \cdot 6^{2}}{12} = 9$ $I=(3*6^2)/12=9$ $k g - m^{2}$ $kg-m^2$
$ω = 2 π \cdot 5 = 31.4$ $omega=2pi * 5=31.4$ $\frac{r a d}{s}$ $(rad)/s$
$t = 4$ $t=4$ $s$ $s$

Thus we can now evaluate the torque
$τ = I \cdot \frac{ω}{t}$ $tau=I*omega/t$
$τ = 9 \cdot \frac{31.4}{4} = 657.75$ $tau=9*31.4/4=657.75$ $N - m$ $N-m$

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What torque would have to be applied to a rod with a length of $6 m$ $6 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency $5 H z$ $5 Hz$ over $4 s$ $4 s$ ?

1 Answer

Explanation:

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Science

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What torque would have to be applied to a rod with a length of 6m6 m and a mass of 3kg3 kg to change its horizontal spin by a frequency 5Hz5 Hz over 4s4 s?

1 Answer

Explanation:

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What torque would have to be applied to a rod with a length of $6 m$ $6 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency $5 H z$ $5 Hz$ over $4 s$ $4 s$ ?