What torque would have to be applied to a rod with a length of $5 m$ and a mass of $2 kg$ to change its horizontal spin by a frequency of $9 Hz$ over $6 s$ ?

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What torque would have to be applied to a rod with a length of $5 m$ and a mass of $2 kg$ to change its horizontal spin by a frequency of $9 Hz$ over $6 s$ ?

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Answer 1 · 2016-02-21T14:05:13

$L=(25*pi)/2$

Explanation:

$L=alpha*I$
$"(L:torque ;alpha :angular acceleration ;I:the moment of inertia)"$
$alpha=(Delta omega)/(Delta t)$
$alpha=(2*pi*Delta f)/(Delta t)$
$alpha=(2*pi*9)/6$
$alpha=3*pi$
$I=1/12*m*l^2 " for a rod spinning around its center"$
$I=1/12*2*5^2=25/6$
$L=3*pi*25/6$
$L=(25*pi)/2$

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What torque would have to be applied to a rod with a length of $5 m$ and a mass of $2 kg$ to change its horizontal spin by a frequency of $9 Hz$ over $6 s$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

What torque would have to be applied to a rod with a length of 5 m5 m and a mass of 2 kg2 kg to change its horizontal spin by a frequency of 9 Hz9 Hz over 6 s6 s?

1 Answer

Explanation:

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Impact of this question

What torque would have to be applied to a rod with a length of $5 m$ and a mass of $2 kg$ to change its horizontal spin by a frequency of $9 Hz$ over $6 s$ ?