What torque would have to be applied to a rod with a length of $4 m$ $4 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency of $2 H z$ $2 Hz$ over $2 s$ $2 s$ ?

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What torque would have to be applied to a rod with a length of $4 m$ $4 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency of $2 H z$ $2 Hz$ over $2 s$ $2 s$ ?

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Answer 1 · 2016-02-18T14:19:13

$L = 24$ $L=24$

Explanation:

$α = \frac{L}{I}$ $alpha=L/I$
$alpha: angular acceleration$ $"alpha: angular acceleration"$
$L:torque$ $"L:torque"$
$I=moment of inertia$ $"I=moment of inertia"$
$alpha =(Delta omega)/(Delta t)$
$alpha=2/2=1$
$1=L/I$
$L=I$
$L=1/12*m*l^2$
$"moment of inertia for a rod rotating around its center"$
$L=1/2*3*4^2=24$
$L=24$

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What torque would have to be applied to a rod with a length of $4 m$ $4 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency of $2 H z$ $2 Hz$ over $2 s$ $2 s$ ?

1 Answer

Explanation:

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What torque would have to be applied to a rod with a length of $4 m$ $4 m$ and a mass of $3 k g$ $3 kg$ to change its horizontal spin by a frequency of $2 H z$ $2 Hz$ over $2 s$ $2 s$ ?