What torque would have to be applied to a rod with a length of $4 m$ $4"m"$ and a mass of $2 kg$ $2"kg"$ to change its horizontal spin by a frequency $9 Hz$ $9"Hz"$ over $8 s$ $8"s"$ ?

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What torque would have to be applied to a rod with a length of $4 m$ $4"m"$ and a mass of $2 kg$ $2"kg"$ to change its horizontal spin by a frequency $9 Hz$ $9"Hz"$ over $8 s$ $8"s"$ ?

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Answer 1 · 2016-02-13T09:16:20

Use following formula and calculate

Explanation:

Torque ( $τ$ $tau$ ) = moment of inertia (I)X angular acceleration ( $α$ $alpha$ )
I = $\frac{1}{12} M L^{2}$ $1/12ML^2$ , where mass M =2kg, Length L= 4m
$α = \frac{d ω}{d t}$ $alpha=(domega)/dt$ = $2 π$ $2pi$ xrate of change of frequency
= 2x3.14x9/8 rads^-2
pl proceed and get result

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What torque would have to be applied to a rod with a length of $4 m$ $4"m"$ and a mass of $2 kg$ $2"kg"$ to change its horizontal spin by a frequency $9 Hz$ $9"Hz"$ over $8 s$ $8"s"$ ?

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What torque would have to be applied to a rod with a length of 4m4"m" and a mass of 2kg2"kg" to change its horizontal spin by a frequency 9Hz9"Hz" over 8s8"s"?

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What torque would have to be applied to a rod with a length of $4 m$ $4"m"$ and a mass of $2 kg$ $2"kg"$ to change its horizontal spin by a frequency $9 Hz$ $9"Hz"$ over $8 s$ $8"s"$ ?