What torque would have to be applied to a rod with a length of 3 m and a mass of 4 kg to change its horizontal spin by a frequency 5 Hz over 4 s?
1 Answer
Nov 14, 2017
94.25 Nm
Explanation:
Torque is rate of change of angular momentum.
= ((mr^2)/3 2piDeltaf)/t ……[∵ Moment of inertia of rod about an axis through its one end and perpendicular to plane is(mr^2)/3 ]
= ((4 kg × (3 m)^2)/3 2pi × 5Hz)/(4s)
= 94.25 Nm
