What torque would have to be applied to a rod with a length of 1m and a mass of 1kg to change its horizontal spin by a frequency of 3Hz over 3s?

1 Answer
Feb 9, 2017

τnet=112kg ms20.833kg ms2

Explanation:

Assuming the rod in question rotates about the center (not the end), we know that

Step 1. Gather the information that you know and need

Mass of rod: mass=m=1 kg
Length of rod: length=L=1 m
Change in angular speed: dω=3 Hz
Change in time: dt=3 s
Torque required: ??

Step 2. Determine the formula using the above givens

Torque: τnet=Iα

  • I is the moment of inertia of our rod
  • Assuming center spin, Irod=1/12mL
  • α is the instantaneous angular acceleration
  • α=dω/dt with units rad/s2 or s2

Torque: τnet=112mLdωdt

Step 3. Plug your knows into the formula for torque

τnet=112(1 kg)(1 m)3 Hz3 s=112kg ms2