What sound intensity corresponds to 92 db?

1 Answer
Trevor Ryan.
Oct 18, 2015

0,00158W//m^2

Explanation:

Sound level beta = 10log(I/(I_0)), where I_0 is the threshold or reference intensity corresponding to the minimum sound that a normal human ear can hear and is assigned a value of 10^(-12) W//m^2

So in this case, 92=10log(I/(10^(-12)))

therefore I=10^(9,2)*10^(-12)=10^(-2,8) W//m^2

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