What's the equation for this?

Question

1015 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-07T19:32:07

$y = (x-4)/(x^2-16)$

There is a vertical asymptote at x = -4 and a horizontal asymptote at y = 0 means:

$y = 1/(x+4)$

There is a removable discontinuity at $x = 4$ means there is a common factor in the numerator and denominator of $x-4$ :

$y = 1/(x+4)*(x-4)/(x-4)$

$y = (x-4)/(x^2-16)$

Check that the y intercept is $(0,1/4)$

$y = (0-4)/(0^2-16)$

$y = 1/4$

This checks