What’s the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65.0% oxygen?
1 Answer
Jul 16, 2014
Explanation:
Solution:
1) Assume
"Li" => 18.7 % or"18.7 g" of"Li" "C" => 16.3 % or"16.3 g" of"C" "O" => 65.0% or"65 g" of"O"
2) Calculate the number of moles of each element.
So
3) Divide by the lowest, seeking the smallest whole-number ratio:
4 ) The empirical formula is