What's the electronic configuration for an atom that has 33 electrons?

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Answer 1 · 2015-01-06T11:05:46

The (neutral) atom that has 33 electrons is called Arsenic ( $As$ ), and its electron configuration can be written like this:

$"As":1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(10)4p^(3)$

Another way to write the electron configuration for $As$ is to use the noble gas shorthand notation. This is done by determining the noble that comes before $As$ in the periodic table, which is Argon ( $Ar$ ).

The electron configuration for $Ar$ is

$"Ar": 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)$

Using this to replace the matching portion of $As$ ' configuration will give

$"As": ["Ar"]4s^(2)3d^(10)4p^(3)$