What's the derivative of $y= arctan(sqrtx)$ ?

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Answer 1 · 2016-03-15T18:23:14

$f'(x)=(1)/(2sqrt(x)(x+1)$

$f(x)=arctan(sqrt(x))$

Apply the chain rule:

$f'(x)=(1)/(x+1).(dsqrt((x)))/(dx)$

$f'(x)=((1)/(2sqrt(x)))/((x+1))$

$f'(x)=(1)/(2sqrt(x)(x+1))$

What's the derivative of y= arctan(sqrtx)y= arctan(sqrtx)?