#C_5H_7Br + NaOEt rarr C_5H_6 +NaBrdarr +EtOH#
#C_5H_6 + NaOEt rarr [C_5H_5]^(-)Na^(+) +EtOH#
#"1 equiv"# gives the diene, #C_5H_6#; the 2nd equiv gives cyclopentadienyl anion. These days, in inorganic laboratories, you can prepare #100*g# quantities of base-free #NaCp# simply by boiling up sodium metal with dicyclopentadiene, #C_10H_12#,