What product do you get when you react 3-bromocyclopentene with $N a O C H_{2} C H_{3}$ $NaOCH_2CH_3$ dissolved in $H O C H_{2} C H_{3}$ $HOCH_2CH_3$ ?

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What product do you get when you react 3-bromocyclopentene with $N a O C H_{2} C H_{3}$ $NaOCH_2CH_3$ dissolved in $H O C H_{2} C H_{3}$ $HOCH_2CH_3$ ?

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Answer 1 · 2016-08-14T06:40:44

$Sodium cyclopentadienide?$ $"Sodium cyclopentadienide?"$

Explanation:

$C_{5} H_{7} B r + N a O E t \to C_{5} H_{6} + N a B r ↓ + E t O H$ $C_5H_7Br + NaOEt rarr C_5H_6 +NaBrdarr +EtOH$

$C_{5} H_{6} + N a O E t \to {[C_{5} H_{5}]}_{5}^{-} N a^{+} + E t O H$ $C_5H_6 + NaOEt rarr [C_5H_5]^(-)Na^(+) +EtOH$

$1 equiv$ $"1 equiv"$ gives the diene, $C_{5} H_{6}$ $C_5H_6$ ; the 2nd equiv gives cyclopentadienyl anion. These days, in inorganic laboratories, you can prepare $100 \cdot g$ $100*g$ quantities of base-free $N a C p$ $NaCp$ simply by boiling up sodium metal with dicyclopentadiene, $C_{10} H_{12}$ $C_10H_12$ ,

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What product do you get when you react 3-bromocyclopentene with $N a O C H_{2} C H_{3}$ $NaOCH_2CH_3$ dissolved in $H O C H_{2} C H_{3}$ $HOCH_2CH_3$ ?

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What product do you get when you react 3-bromocyclopentene with NaOCH2CH3NaOCH_2CH_3 dissolved in HOCH2CH3HOCH_2CH_3?

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What product do you get when you react 3-bromocyclopentene with $N a O C H_{2} C H_{3}$ $NaOCH_2CH_3$ dissolved in $H O C H_{2} C H_{3}$ $HOCH_2CH_3$ ?