What mass of oxygen is needed to react with 4.5g of ethane $C_2H_8$ ?

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Answer 1 · 2016-10-09T18:22:45

We need approx. $17*g$ of dioxygen.

A balanced chemical equation is required:

$H_3C-CH_3 + 7/2O_2(g) rarr 2CO_2(g) +3H_2O(g)$

And thus each equiv ethane requires $7/2$ equiv of dioxygen.

$"Moles of ethane"$ $=$ $(4.5*g)/(30.07*g*mol^-1)$ $=$ $0.15*mol$

And thus we need:

$7/2xx0.15*molxx32.00*g*mol^-1" dioxygen gas"$ $=$ $??g$

What mass of oxygen is needed to react with 4.5g of ethane C_2H_8C_2H_8?