What mass of nitrogen dioxide is produced by the reaction of 8.735g of copper with nitric acid?

1 Answer
Meave60
Jul 3, 2018

#"12.65 g NO"_2"# can be produced.

Explanation:

Start with a balanced equation.

#"Cu(s) + 4HNO"_3("aq")"##rarr##"Cu(NO"_3)_2("aq") + "2NO"_2("g") + "2H"_2"O(l)"#

Calculate mol #"Cu"# by dividing its given mass by its molar mass #("63.546 g/mol")#. Do this by multiplying by the inverse of its molar mass (mol/g). Then multiply by the mol ratio between #"Cu"# and #"NO"_2"# in the balanced equation, with #"NO"_2"# in the numerator. Then calculate the mass of #"NO"_2"# by multiplying by the molar mass of #"NO"_2"#, #("46.005 g/mol")#.

#8.735color(red)cancel(color(black)("g Cu"))xx(1color(red)cancel(color(black)("mol Cu")))/(63.546color(red)cancel(color(black)("g Cu")))xx(2color(red)cancel(color(black)("mol NO"_2)))/(1color(red)cancel(color(black)("mol Cu")))xx(46.005"g NO"_2)/(1color(red)cancel(color(black)("mol NO"_2)))="12.65 g NO"_2"#

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