What mass of iron has a volume of $6.3$ $6.3$ $c m^{3}$ $cm^3$ ?

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Answer 1 · 2018-03-18T05:23:44

$~~49.52 \ "g"$

Iron has a density of $7.86 \ "g/cm"^3$ .

The density formula is:

$rho=m/V,$

where $rho$ is density, $m$ is mass, and $V$ is volume.

To find the mass given the density, we use the equation:

$m=rho*V$

So, plugging in the given values, we get

$m=(7.86 \ "g")/(color(red)cancelcolor(black)("cm"^3))*6.3color(red)cancelcolor(black)("cm"^3)$

$~~49.52 \ "g"$

What mass of iron has a volume of 6.36.36.3 cm^3cm3cm^3?