What mass of aluminum chloride could theoretically be made from 8.1 g of aluminum and excess chlorine?

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What mass of aluminum chloride could theoretically be made from 8.1 g of aluminum and excess chlorine?

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Answer 1 · 2016-05-16T16:05:46

Approx. #40*g#

Explanation:

#"Moles of aluminum "=(8.1*g)/(26.98*g*mol^-1)# #=# #0.300*mol#

#Al(s) + 3/2Cl_2(g) rarr AlCl_3(s)#

Given the 1:1 stoichiometry between Al and the product, if all the aluminum were oxidized, #0.300*molxx133.34*g*mol^-1" aluminum trichloride"# would result, approx. 40 g.

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What mass of aluminum chloride could theoretically be made from 8.1 g of aluminum and excess chlorine?

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