What is x if #x-3/x^2+14=8#?

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Answer 1 · 2017-10-14T04:52:04

#x-3/x^2 + 14 =8#

Subtract 8 from each side:
#x - 3/x^2 + 6 = 0#

Multiply each side by #x^2#:
#(x^2)(x - 3/x^2 + 6) = 0#

Distribute and simplify:
#x^3 - 3 + 6x^2 =0#

#0 = x^3 + 6x^2 - 3#

From here, I think the best option to solve this would be to use a graphing calculator. On the TI-84 plus, I used the numeric solver.

#x = -.671, x=.756, x=5.914#