What is uranium's electron configuration?

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What is uranium's electron configuration?

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Answer 1 · 2014-06-18T05:12:07

The electron configuration for Uranium (U) is based upon the placement of uranium in the fourth column of the actinide series or f block. Therefore th electron configuration for uranium must end as $5 f^{4}$ $5f^4$ ,

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p^{6} 6 s^{2} 4 e^{14} 5 d^{10} 6 p^{6} 7 s^{2} 5 f^{4}$ $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5 p^6 6s^2 4e^14 5d^10 6p^6 7s^2 5f^4$

This notation can be written in core notation or noble gas notation by replacing the $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{2} 4 d^{10} 5 p^{6} 6 s^{2} 4 e^{14} 5 d^{10} 6 p^{6}$ $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5 p^6 6s^2 4e^14 5d^10 6p^6$ with the noble gas [Rn].

$[R n] 7 s^{2} 5 f^{4}$ $[Rn] 7s^2 5f^4$

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What is uranium's electron configuration?

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