What is the VSEPR shape of $S O_{2}$ $SO_2$ ?

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What is the VSEPR shape of $S O_{2}$ $SO_2$ ?

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Answer 1 · 2016-03-21T06:10:46

The molecule is bent around the central sulfur, with an $∠ O - S - O$ $/_O-S-O$ $=$ $=$ $< 120^{\circ}$ $<120""^@$ .

Explanation:

There are 18 valence electrons to distribute around the molecule; and the least electronegative atom, sulfur, is ASSUMED to be central.

Resonance structures of $^{-} O - S^{+} = O$ $""^(-)O-S^(+)=O$ and $^{-} O - S^{2 +} - O^{-}$ $""^(-)O-S^(2+)-O^-$ are valid. In either case there are 3 regions of electron density around the central sulfur: a lone pair, and $2 \times S - O$ $2xxS-O$ bonds, The electronic geometry should be based on a trigonal plane. But, because we describe molecular geometry on the basis of bonds not electron pairs, we describe the geometry of $S O_{2}$ $SO_2$ as bent. The actual molecule has $∠ O - S - O$ $/_O-S-O$ $=$ $=$ $119^{\circ}$ $119""^@$ .

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What is the VSEPR shape of $S O_{2}$ $SO_2$ ?

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