What is the volume of one mole of any gas at STP?

2 Answers
Dr. Hayek
Nov 19, 2015

22.4L

Explanation:

The volume of one mole of an ideal gas at STP can be found as follows:

First, What is STP?

STP is the standard conditions of Temperature and Pressure, where, T=273K and P=1atm.

Since we are looking for the volume of one mole, then n=1mol.

Using the ideal gas law: PV=nRT we can find the volume by:

V=(nRT)/P =(1cancel(mol)xx0.08206(L*cancel(atm))/(cancel(K)*cancel(mol))xx273cancel(K))/(1cancel(atm))=22.4L

Meave60
Nov 19, 2015

The volume of one mole of a gas is either "22.414 L", or "22.711 L", depending on the pressure used for "STP".

Explanation:

It depends on what values you use for "STP". If you use the values of "273.15 K" and "1 atm", the volume of one mole of a gas is "22.414 L".

However, the IUPAC and NIST have updated the values for "STP" to "273.15 K" and "10"^5 "Pa" or "100 kPa". With these values, the volume of one mole of a gas is "22.711 L".

http://en.citizendium.org/wiki/Reference_conditions_of_gas_temperature_and_pressure#Molar_volume_of_a_gas

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