Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the volume of 36.8 g of carbon monoxide at STP?

1 Answer

May 9, 2016

#V=29.4L#

Explanation:

Let us first find the number of mole of carbon monoxide in #36.8g#:

#n=m/(MM)=(36.8cancel(g))/(28.0cancel(g)/(mol))=1.31mol#

At STP, the molar volume is equal to #22.4L/(mol)#, therefore, the volume that will be occupied by #36.8g# carbon monoxide is:

#V=1.31cancel(mol)xx(22.4L)/(1cancel(mol))=29.4L#

Related questions

See all questions in Molar Volume of a Gas

Impact of this question

4192 views around the world

You can reuse this answer
Creative Commons License