What is the volume of 0..23 kg of pure water?

1 Answer
anor277
Oct 16, 2016

#"Density"="Mass"/"Volume"#

Here, #"Volume"# #=# #230*mL#

Explanation:

So #rho# #=# #"Density"="Mass"/"Volume"#

And of course, #"volume"# #=# #"Mass"/rho#

For water, #rho# #=# #1*g*mL^-1#

So #"volume"# #=# #(0.23*cancel(kg)xx10^3*cancelg*cancel(kg^-1))/(1*cancelg*mL^-1)# #=# #230(1/(mL^-1))# #=# #230*mL#.

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