What is the volume in mL of a 0.606 M KOH solution containing 0.023 mol of solute?

1 Answer
anor277
Nov 23, 2017

We use the quotient....#"Concentration"="Moles of solute"/"Volume of solution"'#

Explanation:

And thus #"Volume"="Moles of solute"/"Concentration"#

#=(0.023*cancel(mol))/(0.606*cancel(mol)*L^-1)=3.80xx10^-2*1/(1/L)=3.80xx10^-2*L#

And since there are #1000*mL*L^-1#, we gots a volume of #38*mL#.

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