What is the variance of {8, 19, 10, 0, 1, 0}?

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Answer 1 · 2016-03-15T09:45:04

$sigma^2=428/9=47.5556$

From the given: $n=6$

We solve for arithmetic mean first.

$barx=(8+19+10+0+1+0)/6=38/6=19/3$

The formula for variance of ungrouped data is

$sigma^2=(sum (x-barx)^2)/n$

$sigma^2=((8-19/3)^2+(19-19/3)^2+(10-19/3)^2+(0-19/3)^2+(1-19/3)^2+(0-19/3)^2)/6$

$sigma^2=428/9=47.5556$

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