What is the variance of {51, 3, 9, 15, 3, -9, 20, -1, 5, 3, 2}?

1 Answer
Leland Adriano Alejandro
Mar 12, 2016

Variance#" " "sigma^2=27694/121=228.876#

Explanation:

Compute the mean #barx# first

#barx=(51+3+9+15+3+(-9)+20+(-1)+5+3+2)/11=101/11#

Variance#" " "sigma^2=(sum(x-barx)^2)/n#

#" " "sigma^2#
#=((51-101/11)^2+(3-101/11)^2+(9-101/11)^2+(15-101/11)^2+ (3-101/11)^2+(-9-101/11)^2+(20-101/11)^2+(-1-101/11)^2+(5-101/11)^2+ (3-101/11)^2+(2-101/11)^2)/11#

#" " "sigma^2=27694/121=228.876#

God bless....I hope the explanation is useful.

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