What is the variance of {15, 9, -3, 8, 0}?

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Answer 1 · 2016-03-15T09:58:43

Variance $sigma^2=1054/25=42.16$

We compute the arithmetic mean first

$mu=(15+9+(-3)+8+0)/5$

$mu=29/5$

To compute for variance $sigma^2$ use the formula

$sigma^2=(sum (x-mu)^2)/n$

$sigma^2=((15-29/5)^2+(9-29/5)^2+(-3-29/5)^2+(8-29/5)^2+(0-29/5)^2)/5$

$sigma^2=1054/25=42.16$

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