What is the variance of {12, 6, -2, 9, 5, -1}?

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What is the variance of {12, 6, -2, 9, 5, -1}?

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Answer 1 · 2017-07-06T12:41:24

Variance is $25.14$ $25.14$

Explanation:

Data ; $D = {12, 6, - 2, 9, 5, - 1}$ $D= {12, 6 ,-2, 9 , 5 ,-1}$

Variance $(σ^{2})$ $(sigma^2)$ is the average of squared difference from mean.

Mean is $\frac{\sum D}{6} = \frac{29}{6} \approx 4.83 (2 d p)$ $(sumD)/6 =29/6 ~~ 4.83(2dp)$

$σ^{2} =$ $sigma^2 =$
$\frac{{(12 - 4.83)}^{2} + {(6 - 4.83)}^{2} + {(- 2 - 4.83)}^{2} + {(9 - 4.83)}^{2} + {(5 - 4.83)}^{2} + {(- 1 - 4.83)}^{2}}{6} = \frac{150.83}{6} \approx 25.14 (2 d p)$ ${( 12-4.83)^2 + ( 6-4.83)^2 + ( -2-4.83)^2 + ( 9-4.83)^2+ ( 5-4.83)^2+ ( -1 -4.83)^2}/6 =150.83/6 ~~ 25.14(2dp)$

Variance is $25.14$ $25.14$ [Ans]

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What is the variance of {12, 6, -2, 9, 5, -1}?

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