What is the vapor pressure of water at 105°C?

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What is the vapor pressure of water at 105°C?

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Answer 1 · 2017-02-08T12:28:19

You can do this with the Antoine equation:

$log P = A - B/(C+T)$

where:

$P$ is the vapor pressure of water.

$T$ is the water temperature in celsius.

$A,B,$ and $C$ are the Antoine constants for water.

When the water temperature is in the range of $1 - 100^@ "C"$ :

$A=8.07131, B=1730.63, C= 233.426$

When the water temperature is in the range of $99-374^@ "C"$ :

$A=8.14019, B=1810.94, C=244.485$

If you calculate using this way you will get answer in $"torr"$ :

$P = 10^(A - B/(C+T))$

$= 10^{8.14019-{1810.94}/{105+244.485}}$

$= 10^{8.14019-5.18174}$

$= 10^{2.95845}$

$=$ $"908.76 torr"$

This is the water pressure at $105^@ "C"$ .

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What is the vapor pressure of water at 105°C?

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