What is the trigonometric form of $(- 6 - 5 i)$ $(-6-5i)$ ?

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What is the trigonometric form of $(- 6 - 5 i)$ $(-6-5i)$ ?

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Answer 1 · 2018-06-14T07:11:00

$(- 6 - i 5) = (7.81 cos (219.8) + i 7.81 sin (219.8))$ $color(gray)((-6 - i 5) = (7.81 cos (219.8) + i 7.81 sin (219.8))$

Explanation:

$z = (- 6 - i 5)$ $z = (-6 - i 5)$

Polar form $(r, θ)$ $(r, theta)$

$r = ∣ \sqrt{{(- 6)}^{2} + {(- 5)}^{2} | = | \sqrt{61} ∣ = 7.81}$ $r = |sqrt((-6)^2 + (-5)^2| = |sqrt61 | = 7.81$

$θ = arctan (- \frac{5}{- 6}) = arctan (\frac{5}{6}) = 180 + {39.8}^{\circ} = {219.8}^{\circ}, III Quadrant$ $theta = arctan (-5/-6) = arctan (5/6) = 180 + 39.8^@ = 219.8^@, " III Quadrant"$

Trigonometric form of $z = (r cos θ + i r sin θ)$ $z = (rcos theta + i r sin theta)$

$(- 6 - i 5) = (7.81 cos (219.8) + i 7.81 sin (219.8))$ $color(gray)((-6 - i 5) = (7.81 cos (219.8) + i 7.81 sin (219.8))$

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What is the trigonometric form of $(- 6 - 5 i)$ $(-6-5i)$ ?

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Science

Math

Humanities

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What is the trigonometric form of (−6−5i) (-6-5i) ?

1 Answer

Explanation:

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Impact of this question

What is the trigonometric form of $(- 6 - 5 i)$ $(-6-5i)$ ?