What is the trigonometric form of $3 e^( ( pi)/12 i )$ ?

Question

1515 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-06T16:22:56

I found: $3(cos(pi/12)+isin(pi/12))$

You can change it as:
$rhoe^(itheta)=rho(cos(theta)+isin(theta))$
In your case:
$3e^(pi/12i)=3(cos(pi/12)+isin(pi/12))$

What is the trigonometric form of 3 e^( ( pi)/12 i ) 3 e^( ( pi)/12 i ) ?