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What is the trigonometric form of # 3 e^( ( pi)/12 i ) #?

1 Answer

Jan 6, 2016

I found: #3(cos(pi/12)+isin(pi/12))#

Explanation:

You can change it as:
#rhoe^(itheta)=rho(cos(theta)+isin(theta))#
In your case:
#3e^(pi/12i)=3(cos(pi/12)+isin(pi/12))#

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