What is the trigonometric form of 2e7π12i?
1 Answer
Jan 23, 2016
2[cos(7π12)+isin(7π12)]
Explanation:
Euler's theorem states :
eiθ=cosθ+isinθ
⇒2e7π12i=2[cos(7π12)+isin(7π12)]
2[cos(7π12)+isin(7π12)]
Euler's theorem states :
eiθ=cosθ+isinθ
⇒2e7π12i=2[cos(7π12)+isin(7π12)]