What is the trigonometric form of $2 e^{\frac{7 π}{12} i}$ $2 e^( ( 7 pi)/12 i )$ ?

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What is the trigonometric form of $2 e^{\frac{7 π}{12} i}$ $2 e^( ( 7 pi)/12 i )$ ?

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Answer 1 · 2016-01-23T11:07:55

$2 [cos (\frac{7 π}{12}) + i sin (\frac{7 π}{12})]$ $2[ cos((7pi)/12) + isin((7pi)/12) ]$

Explanation:

Euler's theorem states : $e^{i θ} = cos θ + i sin θ$ $e^(itheta) = costheta + isintheta$

$\Rightarrow 2 e^{\frac{7 π}{12} i = 2 [cos (\frac{7 π}{12}) + i sin (\frac{7 π}{12})]}$ $rArr 2e^((7pi)/12 i= 2 [ cos((7pi)/12) + isin((7pi)/12) ]$

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What is the trigonometric form of $2 e^{\frac{7 π}{12} i}$ $2 e^( ( 7 pi)/12 i )$ ?

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What is the trigonometric form of 2e7π12i 2 e^( ( 7 pi)/12 i ) ?

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What is the trigonometric form of $2 e^{\frac{7 π}{12} i}$ $2 e^( ( 7 pi)/12 i )$ ?