What is the trigonometric form of # 2 e^( ( 7 pi)/12 i ) #?
1 Answer
Jan 23, 2016
# 2[ cos((7pi)/12) + isin((7pi)/12) ] #
Explanation:
Euler's theorem states :
# e^(itheta) = costheta + isintheta #
#rArr 2e^((7pi)/12 i= 2 [ cos((7pi)/12) + isin((7pi)/12) ] #
