What is the trigonometric form of $(-1+6i)$ ?

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Answer 1 · 2015-12-28T21:15:21

$sqrt37/_-1,4$

A complex number $x+iy$ in rectangular form may be converted to polar form $r/_theta$ (trigonometric form) as follows :

$r=sqrt(x^2+y^2) and theta =tan^(-1)(y/x)$ .

So in this particular case we get :

$r=sqrt((-1)^2+6^2)=sqrt37$

$theta=tan^(-1)(6/(-1))=-80,5^@=-1,4rad$

What is the trigonometric form of (-1+6i) (-1+6i) ?