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What is the trigonometric form of # (-1+6i) #?

1 Answer

Dec 28, 2015

#sqrt37/_-1,4#

Explanation:

A complex number #x+iy# in rectangular form may be converted to polar form #r/_theta# (trigonometric form) as follows :

#r=sqrt(x^2+y^2) and theta =tan^(-1)(y/x)#.

So in this particular case we get :

#r=sqrt((-1)^2+6^2)=sqrt37#

#theta=tan^(-1)(6/(-1))=-80,5^@=-1,4rad#

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