# What is the surface area of the solid created by revolving #f(x) = xe^(2x) , x in [2,3]# around the x axis?

##### 1 Answer

Jan 1, 2017

Volume :

#### Explanation:

graph{x^2e^(2x) [-5, 5, -10000, 10000]}

The volume =

Now,

#=1/4(x^2e^(4x)--int e^(4x)d(x^2))

Substituting the limits for the difference, the value here is

So, the volume is